Find the first 5 terms of the sequence: a1 = 2, an = -3an-1
okay this one is a bit trickier, but i think you can still do it!
So, I though a2 would be 3 but, that didn't work. @robz8
a2 = -3(a1)... so what is a1 again?
Is it like this: \[a _{n} = -3a _{n-1}\]
It says a1 is 2
yes, so if a1 is 2... and a2 = -3 * 2..... what would that make a2?
a2 would be -6? @robz8
correct, so now that a2 = -6, the next part in the function is a3 = -3(a2) so what would a3 be?
-27? @robz8
nooooooo... not quite, try again. we know that a2 is -6, so a3 = -3*(-6)
but is it written like how i wrote it? @Emilyh117 because the notation counts.
Oooooo. It would be 18. @robz8
there we go... now repeat that pattern 2 more times, and you have the first 5 terms of the recursive equation
Okay. I started the next one and got -54. Then I got 162. @robz8
that is correct! now you have the first 5 terms of the recursive equation!
Yay! Thank you! :) @robz8
yw! @Emilyh117
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