Find the 7th term of the geometric sequence with the given terms: a2 = 768 and a4 = 48; a7 = _____.
did you even try this one by yourself? or did you just post it up?! haha
I tried it haha. I tried to see what the difference was between 768 and 48, then I thought I had to divide that number, but that wasn't the way. @robz8
well you COULD divide that 768 by 48 to see the difference
768/48 = 16
Oh
The geometric sequence if you expand it divides each term by 2
since it is a geometric series, we know that we have to multiply common number to get the next number in the series
@galacticwavesXX actually it is each term by 4
ohh yea my bad its 4 i calculated it wrong in my head
So now that we know each term is multiplied by 1/4 to get the next number, we can take 48 and multiply it by 1/4 three times to get a7
\[\Large a _{n} = a _{1} r ^{n-1 }\] So we know a2 and a4, which means \[\Large a _{2} = a _{1} r ^{2-1 } = 768\] \[\Large a _{4} = a _{1} r ^{4-1 } = 48\] or \[\Large a _{1} r = 768\] \[\Large a _{1} r ^{3 } = 48\]
so what is \[48 * (1/4)^3\] @Emilyh117
I got 3 @robz8
@robz8 why did you multiply 48 by (1/3)^3 that part confuses me?
close... you only did it twice! you need to do it 3 times! @Emilyh117
i mean 1/4*
@galacticwavesXX the numbers are dividing by 4 each time... which is the same as multiplying by (1/4)
Oh. 3/4 @robz8
there ya go! @Emilyh117
ohh ok didn't know you could do it that way
Math is so annoying sometimes haha. Thank you. :) @robz8
Note that you can find a1 and r from these two, and use it to find any term of the sequence... \[\Large a _{1} r = 768\] \[\Large a _{1} r ^{3 } = 48 \]
@Emilyh117 The good part about math is that it never lies to you!
No, but it confuses you and stuff.. @robz8
@Emilyh117 only if you let it confuse you!
Math is my worst subject @robz8
but... but.... it's the coolest subject! @Emilyh117
Haha It's my worst. I hate it because I don't understand it very well, so it makes me mad. @robz8
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