Find the 9th term of the geometric sequence. 3/4, -3/8, 3/16, -3/32, 3/64
okay back to the basics yeah? what number do we keep multiplying to get the next?
\[a _{n} = a \times r ^{n - 1}\]
I don't know. There are negatives. @robz8
where are is the common ration and a is the first term.
@Emilyh117 okay let's just look at the first couple numbers... how do we get from 3/4 to -3/8? how about -3/8 to 3/16?
-1/8? @robz8
hmmmm nooooooo... not quite... does 3/4 * (-1/8) == (3/8)? i don't think it does.. try another number for your denominator
um. 2? @robz8
yes, 2 is in the denominator! so using the formula that @some_someone gave us, where A is 3/4 and R is -1/2... plug in 9 for N and BAM.. you got your 9th term!
I got 0.002929..... ? @robz8
okay, try not to use your calculator when you're doing this... :P @Emilyh117
Haha Okay... I got 3/6 for the fraction part
@robz8
@Emilyh117 where did you get 3/6 from? plugging in A, R, and N, you should get (3/4)*(-1/2)^(9-1)
Oh. I got -3/8 @robz8
-3/8 is the second term. the question asks you to find the 9th term @Emilyh117
Oh my gosh.. So confusing. @robz8
haha calm down, you can do this... @Emilyh117
your first term is 3/4 ...... A the number you multiply each time is -1/2... R the term you want to find is 9.... N the formula to find the Nth term is A*R^(N-1)
Okay. -3/64?
@robz8
hmmm thats not exactly what i got... @Emilyh117
plugging it all in you should get (3/4)*(-1/2)^8
Okay. I got that @robz8
@Emilyh117 okay... so what should your answer be then?
Alright so.. before I do the power, I got -3/8 @robz8
remember your order of operations!!! you must do the power first!
What!? So i would set -1/2^8? @robz8
you must do (-1/2)^8 and THEN multiply that by (3/4) @Emilyh117
OKay
so... what should you get for (-1/2)^8 ??? @Emilyh117
-1/256
not quite..... the power is 8 which is even, meaning that it will be a positive number, not negative you should end up with 1/256 @Emilyh117
Oh. That's what I meant
now just mulitply that by 3/4 and you're good to go! :) @Emilyh117
I got 3/1024
there ya go! see? that wasn't that bad, was it?! @Emilyh117
Hahah no. Sorry. I bet that was a nightmare for you.
well i've had a lot more practice for you. it's hard when you're doing things for the first time! @Emilyh117
Haha. It is. Thank you so much! @robz8
you're very welcome. Now on the next problem you have to do. Just break it down into steps. See what the difference between the numbers is to start @Emilyh117
Okay. Thanks
@Emilyh117 post again if you are having trouble
I will.
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