Trig Help.
\[\sin(\frac{ 3\pi }{ 4})\]
Question?
Use the reference angle to find the exact value of each expression.
3pi/4 is part of the pi/4 family (the reference angle is pi/4). Sine of pi/4 is 1/sqrt2. Since 3pi/4 is in the second quadrant, its sine is still positive and so sin of 3pi/4 = 1/sqrt2, or sqrt2/2.
okay so what is sin(pi/4)?
then, determine if it is positive or negative, depending on the quadrant, which in this case is 2
@robz8 that is where i got stuck, cause my angle was in the second quadrant :/
okay, so i sin positive or negative in the second quadrant?
To write this in a cleaner way (it looks a little weird up there): \[\sin(\frac{ \pi }{ 4 }) = \frac{ \sqrt{2} }{ 2 }\]pi/4 is a reference angle to 3pi/4 |dw:1367636452903:dw| So \[\sin (\frac{ 3\pi }{ 4 }) = \frac{ \sqrt2 }{ 2 }\]
See, what you should really try to get is where sine is positive and negative. That way, you just have to find whatever angle you're looking for's reference angle and then decide if it's pos or neg.
@thechocoluver445 actually the answer is \[-\frac{ \sqrt{2} }{ 2 }\] but i did get till up to \[\frac{ \sqrt{2} }{ 2 } = \sin \frac{ 3\pi }{ 4 }\]
@some_someone No, it's positive. I think you're thinking of cosine.
sin is negative in the 2nd quadrant i believe
No, that's cosine! http://www.regentsprep.org/Regents/math/algtrig/ATT5/UnitCirclePic.pdf
@thechocoluver445 yes! i was looking at the wrong problem :/ lol thnx that is where i was confused i got positive and i thought it said the answer was negative.. thank you all :D
Oh lol that's good to hear! :) But if you're still a little iffy |dw:1367636747657:dw| |dw:1367636793885:dw|
That is why i was confused.
It's ok, happens to the best of us :D
Thank you @thechocoluver445 :D
No problem :)
sin isn't negative until pi... if you look at the sin's graph in cartesian coordinates
right?
it is positive, @robz8 @thechocoluver445 was right.
Yep. Because after pi, you enter quadrants 3 and 4, where sine is negative
oh wow i'm stupid, i was arguing against myself haha
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