Mathematics
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OpenStudy (anonymous):
Find the solutions 1/2x^2+2x+3=0
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OpenStudy (anonymous):
It's basic algebra figure it out.
OpenStudy (anonymous):
I wouldn't be asking for help if I knew how.
OpenStudy (anonymous):
Read the text book...
OpenStudy (anonymous):
Why are you being rude?
OpenStudy (anonymous):
Is that \[\frac{ 1 }{ 2 } x^2 + 2x+3=0\]
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OpenStudy (anonymous):
Yes
OpenStudy (anonymous):
Ok well you can just use expansion in this equation. Have you all learned that?
OpenStudy (anonymous):
No, I haven't. If I have, I don't remember it.
OpenStudy (anonymous):
I don't really get it.
OpenStudy (anonymous):
When the equation in this condition\[ax^{2}+bx+c=0\]
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OpenStudy (anonymous):
SerikMB is better at explaining
OpenStudy (anonymous):
you can apply the formula \[x=\frac{ -b \pm \sqrt{b ^{2}-4ac} }{ 2a }\]
OpenStudy (anonymous):
Well thank you for trying Amber
OpenStudy (anonymous):
I just plug it in?
OpenStudy (anonymous):
yes
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OpenStudy (anonymous):
here you have a=1/2
b=2 and c=3
OpenStudy (anonymous):
note the sign plus/minus, so you can have 2 solutions at quadratic equations
OpenStudy (anonymous):
-\[-2\sqrt{-2}/1\]
OpenStudy (anonymous):
?
OpenStudy (anonymous):
yes, i have noticed that, in this case you have no particular REAL solution
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OpenStudy (anonymous):
So what do I do? Is no solution the answer?
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
Thank you, I appreciate the help.