ln3x=5...plz help!
im not sure if it's \[\frac{ \ln5 }{ \ln3 }\]
Use 'e' when getting rid of ln
e is your friend.
i love e, i just don't know how to use him to his full extent..
\[\large e^{\ln(3x)}=3x\]
Make sure you e both sides
What do you get?
um..\[e^\ln(3x) = e^3x\] ?
More generally: \(e^{ln(anything)}=anything\) and conversely \(ln^{e^{anything}}=anything\)
ahh
I meant \(ln(e^{anything})=anything\) on the second part.
From \[\ln(3x)=5 \] e both sides you get \[e^{\ln(3x)}=e^5 \\ \\\] \[3x=e^5\]
im not sure that can be th final answer...
Well, he did not divide through by 3.... But it is that close to the final answer.
kk
Remember that e is just a number, not a rational one, but it is real enough. So \(\frac{e^5}{3}\) is a real solution.
wow, okay..thx!
Now, if someone asks for a rational, integer, etc. solution, e is no longer your friend. e becomes that guy you know down the street who hangs out what odd crowd, \(\pi\) and the \(\sqrt2\).
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