Question

is this correct?
1/x^2 dx

Answer 1

I got x^-1 + C

Answer 2

or is it -x^-1 + C

Answer 3

@agent0smith

Answer 4

@electrokid

Answer 5

yep

Answer 6

ty :))

Answer 7

the second one

Answer 8

is it because i moved x^2 to the top?

Answer 9

\[
\int {1\over x^2}dx=\int x^{-2}dx
\]

Answer 10

so the answer is x^-1 + C?

Answer 11

\[={x^{-1}\over -1}+c\]

Answer 12

ohh ok ty :)

Answer 13

Remember that after increasing the power by one (to -1), you need to divide by the new power (-1).

Answer 14

\[\Large \int\limits x^{-2}dx = - \frac{ 1 }{ x } +C\]

Answer 15

yeah i forgot about that rule lol