Question

find the derivatives
d/dx(sqrt(xcosx))

Answer 1

\[d/dx \sqrt{xcox}\]

Answer 2

You need product rule followed by chain rule

Answer 3

yes i used that but i made mistake but i dont know where!

Answer 4

What do you have?

Answer 5

\[f(x)=(xcosx)^{1/2}\]
\[f(x)=1/2(xcosx)^{-1/2}\]
\[f(x)=1/2(xcosx)^{1/2} d/dx (xcosx)\] ?

Answer 6

\[f(x)=1/2(xcosx)^{1/2} xsinx?\]

Answer 7

The third line is \[f(x)=1/2(xcosx)^{-1/2} d/dx (xcosx)\]

Answer 8

And as for d/dx(xcosx) you have to use product rule
\[y'=\frac{1}{2}(xcos(x))^{-1/2}[x(-\sin(x)+\cos(x)]\]

Answer 9

i dont understand xcosx part!

Answer 10

I gotta go now

Answer 11

Product rule

Answer 12

Product rule is
\[y=uv \\ \\ y'=udv+vdu\]

Answer 13

I gotta go bye

Answer 14

\[\frac{d}{dx}\sqrt{f(x)}=\frac{f'(x)}{2\sqrt{f(x)}}\] with
\[f(x)=x\cos(x), f'(x)=\cos(x)-x\sin(x)\]

Answer 15

@satellite73
theres not root?