Indicate, in standard form, the equation or inequality that is shown by the graph.
looks a lot like \(y=-x+4\)
\(y\)-itnercept is 4 and slope is \(-1\)
@satellite73 if you have time can you stick here for a lil and help me ?
sure go ahead and post
i have more questions like this that i dont understand
Circle P is tangent to the x-axis and the y-axis. If the coordinates of the center are (r, r), find the coordinates of the points of tangency.
okay did you see how that one was done? the y intercept is where it crosses the y axis
what is the question for that one?
no i didnt exactly understand the process but i het the gist of it
Circle P is tangent to the x-axis and the y-axis. If the coordinates of the center are (r, r), find the coordinates of the points of tangency.
if the center is \((r,r)\) then the points of tangency are \((0,r)\) and \((r,0)\)
yess okay i get that i think
For parallelogram ABCD, A(0, 0), B(a, b), and D(c, 0) are three of its vertices. Find the coordinates of C in terms of a, b, c.
yeah that is more or less straight forward
no that was wrong, hold on a sec
kk
a+c,b
\((a+c,d)\) i think is right yes?
not an option
i am sorry, i meant \((a+c, b)\)
Circle P is tangent to the x-axis and the y-axis. If the coordinates of the center are (r, r), find the slope of the line through the origin and the center.
that slope would be 1
its all good i appreciate you helping me btw
Indicate in standard form the equation of the line passing through the given points. E(-2, 2), F(5, 1)
ok we need the slope first
okay let me get that really quick
from -2 to 5 is right 7, from 2 to 1 is down 1 slope is \(-\frac{1}{7}\)
oh well thank you love:)
yw now you need the point slope formula to get the equation
whats that one again like y=m+a or something like that
\[y-1=-\frac{1}{7}(x-5)\]
lol no that is not the form of anything \[y=mx+b\] is the slope intercept form \[y-y_1=m(x-x_1)\] is the point slope form
you want standard form
oh yes lol okay thank you
which is ?
A+B=?
ugh im not good at remembering formulas i alwys write them down
\[y-1=-\frac{1}{7}(x-5)\] \[7y-7=-x+5\] \[7y+x=12\] i think is the form you want
the one that looks like \[ax+by=c\] or something similar
is it possible its x+7y=12?
yes, you should probably put the \(x\) first
okay :D
Circle P is tangent to the x-axis and the y-axis. If the coordinates of the center are (r, r), find the equation of the line containing the points of tangency.
ow did you get that?
but its not an option
no that was wrong, i read too quickly
x+y=1?
line containing point of tangency \((0,r)\) and \((r,0)\) is \(y=-x+r\)
x-y=r?
or \(x+y=r\) there must be an \(r\) in your answer
slope is \(-1\) to it must be \(x+y=r\)
oh okay i understand how its that
In rectangle ABCD, if the coordinates of A are (0, 0) and of C are (r, s), find the coordinates of B.
\(B=(0,s)\)
it is on the \(y\) axis, so the first coordinate is zero
ohhh right okay
In equilateral triangle RST, R has coordinates (0, 0) and T has coordinates of (2a, 0). Find the coordinates of S in term
on line class?
yup geometry is the only one i have trouble learning online
no one to tell if you are doing it wrong or right
yeah i can see this would be annoying i think a lot of it is algebra of some kind
well it is and i did really goo di nalgebra its just knowhing what formulas to use and what the formulas are
In equilateral triangle RST, R has coordinates (0, 0) and T has coordinates of (2a, 0). Find the coordinates of S in terms of a. (this was a correction of the last one )
first coordinate is \(a\)
second coordinate is \(a\sqrt{3}\)
if it is equilateral so the answer should be \[(a, a\sqrt3)\]
Find the coordinates of the other endpoint if the midpoint is M(8, 2) and the other endpoint is P(5, 6).
nvm that one is easy i know it
Given the points A(0, 0), B(e, f), C(0, e) and D(f, 0), determine if line segments AB and CD are parallel, perpendicular or neither.
i need paper, having trouble keeping all the letters straight in my head hold on
hahha okay thats fine sounds like me
i got confused, but once i wrote it down it seems they are perpendicular
one has slope \(\frac{f}{e}\) other one has slope \(-\frac{e}{f}\)
so their exactopposites which makes them perpendicular
Find the length of the radius of the given circle. (x - 5)2 + (y + 3)2 = 25
i don't know what "exactopposites" means, but if it means "negative reciprocal" then yes
radius is the square root of 25, which is 5
hahahhaha yes you got it, thats what i meant
yayyyy okay how much longer can you stick around?
your really amazing and helpful seriously
i am watching buzby berkley musicals on tcm, and typing at the same time you got more?
yesss prob like a ton but idk how long you can hlep
actually it is busby berkeley
whats that about>/?
go ahead and post, i will tell you when i have had enough
hahahaha okay thank you i appreciate it soo much you have no clue
no problem
okay i have 23 more questions
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