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Mathematics 16 Online
OpenStudy (anonymous):

Indicate, in standard form, the equation or inequality that is shown by the graph.

OpenStudy (anonymous):

OpenStudy (anonymous):

looks a lot like \(y=-x+4\)

OpenStudy (anonymous):

\(y\)-itnercept is 4 and slope is \(-1\)

OpenStudy (anonymous):

@satellite73 if you have time can you stick here for a lil and help me ?

OpenStudy (anonymous):

sure go ahead and post

OpenStudy (anonymous):

i have more questions like this that i dont understand

OpenStudy (anonymous):

Circle P is tangent to the x-axis and the y-axis. If the coordinates of the center are (r, r), find the coordinates of the points of tangency.

OpenStudy (anonymous):

OpenStudy (anonymous):

okay did you see how that one was done? the y intercept is where it crosses the y axis

OpenStudy (anonymous):

what is the question for that one?

OpenStudy (anonymous):

no i didnt exactly understand the process but i het the gist of it

OpenStudy (anonymous):

Circle P is tangent to the x-axis and the y-axis. If the coordinates of the center are (r, r), find the coordinates of the points of tangency.

OpenStudy (anonymous):

if the center is \((r,r)\) then the points of tangency are \((0,r)\) and \((r,0)\)

OpenStudy (anonymous):

yess okay i get that i think

OpenStudy (anonymous):

For parallelogram ABCD, A(0, 0), B(a, b), and D(c, 0) are three of its vertices. Find the coordinates of C in terms of a, b, c.

OpenStudy (anonymous):

yeah that is more or less straight forward

OpenStudy (anonymous):

OpenStudy (anonymous):

no that was wrong, hold on a sec

OpenStudy (anonymous):

kk

OpenStudy (anonymous):

a+c,b

OpenStudy (anonymous):

\((a+c,d)\) i think is right yes?

OpenStudy (anonymous):

not an option

OpenStudy (anonymous):

i am sorry, i meant \((a+c, b)\)

OpenStudy (anonymous):

Circle P is tangent to the x-axis and the y-axis. If the coordinates of the center are (r, r), find the slope of the line through the origin and the center.

OpenStudy (anonymous):

that slope would be 1

OpenStudy (anonymous):

its all good i appreciate you helping me btw

OpenStudy (anonymous):

Indicate in standard form the equation of the line passing through the given points. E(-2, 2), F(5, 1)

OpenStudy (anonymous):

ok we need the slope first

OpenStudy (anonymous):

okay let me get that really quick

OpenStudy (anonymous):

from -2 to 5 is right 7, from 2 to 1 is down 1 slope is \(-\frac{1}{7}\)

OpenStudy (anonymous):

oh well thank you love:)

OpenStudy (anonymous):

yw now you need the point slope formula to get the equation

OpenStudy (anonymous):

whats that one again like y=m+a or something like that

OpenStudy (anonymous):

\[y-1=-\frac{1}{7}(x-5)\]

OpenStudy (anonymous):

lol no that is not the form of anything \[y=mx+b\] is the slope intercept form \[y-y_1=m(x-x_1)\] is the point slope form

OpenStudy (anonymous):

you want standard form

OpenStudy (anonymous):

oh yes lol okay thank you

OpenStudy (anonymous):

which is ?

OpenStudy (anonymous):

A+B=?

OpenStudy (anonymous):

ugh im not good at remembering formulas i alwys write them down

OpenStudy (anonymous):

\[y-1=-\frac{1}{7}(x-5)\] \[7y-7=-x+5\] \[7y+x=12\] i think is the form you want

OpenStudy (anonymous):

the one that looks like \[ax+by=c\] or something similar

OpenStudy (anonymous):

is it possible its x+7y=12?

OpenStudy (anonymous):

yes, you should probably put the \(x\) first

OpenStudy (anonymous):

okay :D

OpenStudy (anonymous):

Circle P is tangent to the x-axis and the y-axis. If the coordinates of the center are (r, r), find the equation of the line containing the points of tangency.

OpenStudy (anonymous):

OpenStudy (anonymous):

ow did you get that?

OpenStudy (anonymous):

but its not an option

OpenStudy (anonymous):

no that was wrong, i read too quickly

OpenStudy (anonymous):

x+y=1?

OpenStudy (anonymous):

line containing point of tangency \((0,r)\) and \((r,0)\) is \(y=-x+r\)

OpenStudy (anonymous):

x-y=r?

OpenStudy (anonymous):

or \(x+y=r\) there must be an \(r\) in your answer

OpenStudy (anonymous):

slope is \(-1\) to it must be \(x+y=r\)

OpenStudy (anonymous):

oh okay i understand how its that

OpenStudy (anonymous):

In rectangle ABCD, if the coordinates of A are (0, 0) and of C are (r, s), find the coordinates of B.

OpenStudy (anonymous):

OpenStudy (anonymous):

\(B=(0,s)\)

OpenStudy (anonymous):

it is on the \(y\) axis, so the first coordinate is zero

OpenStudy (anonymous):

ohhh right okay

OpenStudy (anonymous):

In equilateral triangle RST, R has coordinates (0, 0) and T has coordinates of (2a, 0). Find the coordinates of S in term

OpenStudy (anonymous):

on line class?

OpenStudy (anonymous):

OpenStudy (anonymous):

yup geometry is the only one i have trouble learning online

OpenStudy (anonymous):

no one to tell if you are doing it wrong or right

OpenStudy (anonymous):

yeah i can see this would be annoying i think a lot of it is algebra of some kind

OpenStudy (anonymous):

well it is and i did really goo di nalgebra its just knowhing what formulas to use and what the formulas are

OpenStudy (anonymous):

In equilateral triangle RST, R has coordinates (0, 0) and T has coordinates of (2a, 0). Find the coordinates of S in terms of a. (this was a correction of the last one )

OpenStudy (anonymous):

first coordinate is \(a\)

OpenStudy (anonymous):

second coordinate is \(a\sqrt{3}\)

OpenStudy (anonymous):

if it is equilateral so the answer should be \[(a, a\sqrt3)\]

OpenStudy (anonymous):

Find the coordinates of the other endpoint if the midpoint is M(8, 2) and the other endpoint is P(5, 6).

OpenStudy (anonymous):

nvm that one is easy i know it

OpenStudy (anonymous):

Given the points A(0, 0), B(e, f), C(0, e) and D(f, 0), determine if line segments AB and CD are parallel, perpendicular or neither.

OpenStudy (anonymous):

i need paper, having trouble keeping all the letters straight in my head hold on

OpenStudy (anonymous):

hahha okay thats fine sounds like me

OpenStudy (anonymous):

i got confused, but once i wrote it down it seems they are perpendicular

OpenStudy (anonymous):

one has slope \(\frac{f}{e}\) other one has slope \(-\frac{e}{f}\)

OpenStudy (anonymous):

so their exactopposites which makes them perpendicular

OpenStudy (anonymous):

Find the length of the radius of the given circle. (x - 5)2 + (y + 3)2 = 25

OpenStudy (anonymous):

i don't know what "exactopposites" means, but if it means "negative reciprocal" then yes

OpenStudy (anonymous):

radius is the square root of 25, which is 5

OpenStudy (anonymous):

hahahhaha yes you got it, thats what i meant

OpenStudy (anonymous):

yayyyy okay how much longer can you stick around?

OpenStudy (anonymous):

your really amazing and helpful seriously

OpenStudy (anonymous):

i am watching buzby berkley musicals on tcm, and typing at the same time you got more?

OpenStudy (anonymous):

yesss prob like a ton but idk how long you can hlep

OpenStudy (anonymous):

actually it is busby berkeley

OpenStudy (anonymous):

whats that about>/?

OpenStudy (anonymous):

go ahead and post, i will tell you when i have had enough

OpenStudy (anonymous):

http://www.youtube.com/watch?v=_r3KdTL6mjk

OpenStudy (anonymous):

hahahaha okay thank you i appreciate it soo much you have no clue

OpenStudy (anonymous):

no problem

OpenStudy (anonymous):

okay i have 23 more questions

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