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sam (.sam.):
OpenStudy (anonymous):
So @.Sam. which all have i done right
sam (.sam.):
All good except for E
OpenStudy (anonymous):
So how do we have to do e
OpenStudy (unklerhaukus):
@u0860867
i think you found
\[\lim_{x\to\pi/2^-}\tan x=\infty\]
but the question is
\[\lim_{x\to\pi/2^+}\tan x\]
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OpenStudy (anonymous):
E asks is the limit approaching from the right of pi/2
sam (.sam.):
Yeah exactly unkle, we got the vertical asymptote at 3pi/2, So as x approaches pi/2, with asymptote at 3pi/2 you will get -infinity because its at the left side of the asymtotes
sam (.sam.):
Picture
OpenStudy (anonymous):
so i just ned to put a negative sign infront of my answer
sam (.sam.):
Yes
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