Question

URGENT!!!!!! I need someone to help me go through the steps of solving for v in this equation:

Answer 1

\[L=\frac{ v _{c}^{2}\cos \theta sen \theta -v _{c}\cos \theta \sqrt{v _{c}^{2}\sin ^{2}\theta-2g(h _{C}-h _{D})} }{ g }\]

Answer 2

what is sen(theta)?

Answer 3

Like the numerical value of sin theta? It is just the factor that transforms v into a component in the y direction.

Answer 4

is it supposed to be sin(theta)

Answer 5

Ahhh yeah. I speak spanish so for me sine is seno, it slipped sorry. Yes it is sin(theta)

Answer 6

no problem.

Answer 7

@satellite73

Answer 8

first multiply both sides by g

Answer 9

then subtract the term vc^2cos(theta)*(sin(theta)) from both sides.

Answer 10

then divide both sides by -vc*cos(theta)

Answer 11

then square both sides.

Answer 12

give me one sec. ill post a picture.

Answer 13

I did what you said but I got stuck again at:\[\frac{ L ^{2}g ^{2} }{ 2\cos(\theta) }=v _{c}^{2}(\cos(\theta)g(h _{C}-h _{D})+Lgsin (\theta)-v _{c}^{2}\cos(\theta)sen ^{2}(\theta))\]

Answer 14

at the end it should be + or - square root.

Answer 15

Thank you!!!!!!!!! That was great.

Answer 16

you're welcome

Answer 17

But where did the cos squared go in the eight step?