Question

Can someone please check my answer ....

Answer 1

you can break the 2nd integral into 2 parts:
\[\int\limits_{-2}^{4}(f(x)+8) dx=\int\limits_{-2}^{4}f(x) dx + \int\limits_{-2}^{4}8 \ dx\]

Answer 2

They tell you what the first integral is.
however, you must do the integration on the second one.

Answer 3

right but don't you just do 8+5=13 and that is your answer

Answer 4

as you remember from the previous question, you can "pull out" the 8.
so you need to figure out
\[ 8 \int_{-2}^4 dx \]
can you do that ?

Answer 5

yup give me a minute

Answer 6

I get 0

Answer 7

how ?

Answer 8

I think I am doing it wrong what did you get?

Answer 9

the integral of dx is x
can you finish ?

Answer 10

6

Answer 11

and don't forget the 8 out front

Answer 12

48

Answer 13

now add in the first integral which they tell you is 5

Answer 14

53 is my final answer then?

Answer 15

yes. Do you see how to do this? when you got 13, you were thinking something wrong (like the 8 was not inside the integral)

The important thing is get your thinking straight.

Answer 16

yup got it