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Mathematics 17 Online
OpenStudy (anonymous):

Choose the equation below that corresponds to the graph shown. graph of a u-shaped figure opening downward with a maximum point of (−2, 5) y = 2x2 + 8x − 3 y = −2x2 + 8x − 3 y = 2x2 − 8x − 3 y = −2x2 − 8x − 3

OpenStudy (anonymous):

OpenStudy (anonymous):

vertex is at \((-2,5)\) so you might try \[y=2(x+2)^2-5\]

OpenStudy (anonymous):

all your options have a leading coefficient of 2, so you know it has to look like that one

OpenStudy (anonymous):

multiply out and see what you get if you still need help let me know

OpenStudy (anonymous):

i got a

OpenStudy (anonymous):

yeah and i am an idiot, sorry for confusing you the parabola opens DOWN not up, so it is \[y=-2(x+2)^2+5\]

OpenStudy (anonymous):

or \[y=-2x^2-8x-3\]

OpenStudy (anonymous):

so d?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

can you help me with this? Find the vertex of the quadratic equation: y = 2x2 + 8x − 4. (−2, 20) (−2, −12) (2, 20) (−2, −28)

OpenStudy (anonymous):

yes to find the vertex, the first coordinate is always \(-\frac{b}{2a}\) which in your case is \(-\frac{8}{2\times 2}=-2\)

OpenStudy (anonymous):

the second coordinate is what you get when you replace \(x\) by \(-2\)

OpenStudy (anonymous):

in this case you get \[2\times (-2)^2+8\times -2-4=8-16-4=-8-4=-12\]

OpenStudy (anonymous):

making your vertex \((-2,12)\)

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