Choose the equation below that corresponds to the graph shown. graph of a u-shaped figure opening downward with a maximum point of (−2, 5) y = 2x2 + 8x − 3 y = −2x2 + 8x − 3 y = 2x2 − 8x − 3 y = −2x2 − 8x − 3
vertex is at \((-2,5)\) so you might try \[y=2(x+2)^2-5\]
all your options have a leading coefficient of 2, so you know it has to look like that one
multiply out and see what you get if you still need help let me know
i got a
yeah and i am an idiot, sorry for confusing you the parabola opens DOWN not up, so it is \[y=-2(x+2)^2+5\]
or \[y=-2x^2-8x-3\]
so d?
yes
can you help me with this? Find the vertex of the quadratic equation: y = 2x2 + 8x − 4. (−2, 20) (−2, −12) (2, 20) (−2, −28)
yes to find the vertex, the first coordinate is always \(-\frac{b}{2a}\) which in your case is \(-\frac{8}{2\times 2}=-2\)
the second coordinate is what you get when you replace \(x\) by \(-2\)
in this case you get \[2\times (-2)^2+8\times -2-4=8-16-4=-8-4=-12\]
making your vertex \((-2,12)\)
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