Question

Verify the idenity: 1-cos2x/1+sinx=sin x

Answer 1

1 - cos2x = 2sin^2(x)

Answer 2

is a rule. should help. lmk if i should solve

Answer 3

you're making it more complicated :P

Answer 4

ya i think so lol

Answer 5

2sinx = 1 + sinx can be obtained from the first line

Answer 6

by dividing both sides by sinx

Answer 7

ah

Answer 8

answer is sinx = 1/2 --> x = pi/6

Answer 9

hmm? its just a proof

Answer 10

\[2\sin^{2} x = \sin x + \sin^{2} x\]
\[\sin^{2} x = \sin x\]
\[\sin^{2} x - \sin x = 0\]
\[\sin x (\sin x - 1) = 0\]
x = 0, pi/2,pi

Answer 11

why do u solve for x

Answer 12

hmm its not an identity if its not true for all "x"

Answer 13

oh i see okay

Answer 14

You need to prove how the left hand side equals to sin x when simplified.

Answer 15

its not possible in this case, thats what i thought

Answer 16

its asking u to verify if it equal

Answer 17

maybe its not written clearly...can you use the equation editor

Answer 18

Verify each identity:
\[1+\frac{ \cos ^{2}x }{ 1+\sin x }=\sin x\]

Answer 19

1-

Answer 20

ok
\[\cos^{2} x = 1-\sin^{2} x = (1+\sin x)(1-\sin x)\]

Answer 21

\[1-\frac{(1+sinx)(1-sinx) }{1+\sin x }=sinx\]
\[1- (1-sinx)=\sin x\]

Answer 22

From here what happens to the negative infront of the sin x so that it can be equal to positive sin x

Answer 23

2 neg make a pos

-(-sin x) = sin x