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Mathematics 19 Online
OpenStudy (anonymous):

Use the elimination method to solve. Show all work: 2x + 5y = −3 −15x − 5y = −10

OpenStudy (e.mccormick):

Do you know what the elimination method is?

OpenStudy (anonymous):

not really :/

OpenStudy (e.mccormick):

OK. That is where you add a multple of one row to another and use the result to replace eiher of the rows. In this case, you have a 5y and a -5y so the multiple is easy. 1.

OpenStudy (e.mccormick):

Does that make sense? I can set it up so you can see what I am talking about.

OpenStudy (anonymous):

Yeah can you set it up I was trying to understand but it's still not very clear to me

OpenStudy (e.mccormick):

Yah, without an example, this is a bit hard to grasp.

OpenStudy (e.mccormick):

\[\begin{array}{rrr} 2x & +5y &= -3\\ -15x & -5y & = -10 \end{array}\] Now add them together by columns. \[\begin{array}{rrr} 2x\downarrow & +5y\downarrow &= -3\downarrow\\ -15x\downarrow & -5y\downarrow & = -10\downarrow\\ 2x-15x&+5y-5y&=-3-10\\ -13x&0y&=-13\\ \end{array}\]

OpenStudy (e.mccormick):

Now, you can use that new row to replace one of the existing rows. In this case, it will not take much after that to solve it.

OpenStudy (anonymous):

x=1 y=-1?

OpenStudy (e.mccormick):

Lets see. The x=1 is easy... yah. That is is.

OpenStudy (e.mccormick):

Now can you guess where the name "elimination" comes from?

OpenStudy (e.mccormick):

The way they were added together, the y term became 0, and was eliminated. That is what the name means and is the goal of doing this. If nothing is negative and matching, you multiply through by a negative that makes something match, -1, -5, -whatever. Then add and the negative matched term is eliminated.

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