Five marbles are randomly selected with replacement. The probability that a black marble is chosen is 15%. What is the probability that at least 2 marbles are black?
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OpenStudy (anonymous):
I don't know what that means. ^^^
OpenStudy (anonymous):
well if one marbel is 15% then two marbels would be 30%
OpenStudy (anonymous):
at least two are black, easier to compute
none are black
one is black
then subtract the result from 1
OpenStudy (anonymous):
That's what I was thinking, but that isn't an option. @skinny23
OpenStudy (anonymous):
that is because it is wrong
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OpenStudy (anonymous):
what are the options?
OpenStudy (anonymous):
probability that one is black is 15%
probability that one is not black is therefore 84% = .85
probability that none are black out of 5 picks is \(.85^5\)
OpenStudy (anonymous):
probability that exactly one is black is
\[5\times .15\times .85^4\]
OpenStudy (anonymous):
your answer is therefore
\[1-(.85)^5-5\times (.15)\times (.85)^4\]
OpenStudy (anonymous):
0.16, 0.14, 0.86, 0.84 are my options
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