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Mathematics 13 Online
OpenStudy (anonymous):

A computer package sale comes with two different choices of printers and four different choices of monitors. If a store wants to display each packae combination that is for sale, how many packages must be displayed?

OpenStudy (mathstudent55):

|dw:1367875849889:dw|

OpenStudy (anonymous):

Okay, so there's two types of printers. Printer 1 and Printer 2. So far we have: Printer One Printer Two Now, after that, you have four different monitors. So, Monitor 1, Monitor 2, Monitor 3, and Monitor Four. For each of the printers, you have four choices of monitors. Ready? Printer 1 ----->Monitor (M) 1 ----->M 2 ----->M 3 ----->M 4 Printer 2 ----->M 1 ----->M 2 ----->M 3 ----->M 4 And there you have it! So, the monitor choice's arrows would connect to the printers above them. ~Me

OpenStudy (anonymous):

This is a combination problem lke this..\[nCr=\frac{ n! }{ n-r }! r!\]

OpenStudy (anonymous):

or is it a permutation problem?

OpenStudy (mathstudent55):

|dw:1367876138835:dw| 1 x 2 x 4 = 8

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