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Mathematics 19 Online
OpenStudy (anonymous):

How would I solve this? Steps please so I can understand. -5√3 + √27

OpenStudy (anonymous):

@hartnn

OpenStudy (amistre64):

simplfy that 27 into its prime factors

OpenStudy (anonymous):

are you sure?

OpenStudy (amistre64):

if we can get that sqrt(27) to simplify to: n sqrt(3) this will be simple enough

OpenStudy (anonymous):

where did n cum from?

OpenStudy (amistre64):

you are allowed to use nonporn site spellings here ... "come" is proper

OpenStudy (anonymous):

my apologies. it was used for abbr.

OpenStudy (amistre64):

the n (for number) is just standing in at the moment, the important thing is that we want to simplify that sqrt(27) into that form

OpenStudy (anonymous):

okay:)

OpenStudy (anonymous):

So, simplify sq r 27 to n square r 3?

OpenStudy (amistre64):

yes, one method is to try to find a perfect square: 1,4,9,16,25,36,... that is a factor of 27

OpenStudy (amistre64):

..and just as a side note :) it is not exponentially difficult to type "come" in order to justify abbreviating it to 3 letters ... just saying :)

OpenStudy (anonymous):

you are ace high with that point, dear

OpenStudy (anonymous):

9!!!

OpenStudy (amistre64):

9 is great we know that we can turn sqrt(9) into 3, such that sqrt(27) = sqrt(9*3) = 3sqrt(3) now that we have some "like" factor, adding them should be a sinch

OpenStudy (amistre64):

-5√3 + √27 -5√3 + √3 (-5+3)√3 -2√3

OpenStudy (amistre64):

forgot the 3 in the second line :/

OpenStudy (anonymous):

where should the 3 be in the third line?

OpenStudy (amistre64):

-5√3 + √27 -5√3 + 3√3 <-- think of this like -5x + 3x, and factor out an x if need be (-5+3)√3 -2√3

OpenStudy (anonymous):

thank you so very much. you're perf

OpenStudy (amistre64):

good luck ;)

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