Help Please! ? :) Just Need The Steps :) 3 + 1 = 6 ------ -------- -- m-4 3(m-4) m
Well, I think that this problem is stating that m=6. If m equals 6 then you can solve for the other ones. 6 - 4 = 2. 3(6 - 4) = 6. So \[\frac{ 2 }{ 6 }\] I think. I am just in eighth grade. At least I tried to help.
The Answer iS 9, iJust Need To Know How They Got Tht
first combine fractions on left \[\frac{3}{m-4} + \frac{1}{3(m-4)} = \frac{9}{3(m-4)}+\frac{1}{3(m-4)} = \frac{10}{3(m-4)}\] then cross-multiply \[\frac{10}{3(m-4)} = \frac{6}{m}\] \[10m = 6*3(m-4)\] \[10m = 18m - 72\] \[8m = 72\] \[m=9\]
Thank You So Much :)
yw
Now I feel dumb. Well, I bet this is like Algebra III or somethin'. I'm just in Math III. Sigh.
Lol... Its Algebra 1
Oh! I am going there next year! :3
Nice :)
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