Question

6+radical 2

State the conjugate and then multiply them together. Please hurry.

Answer 1

Hint: The conjugate of \(\large a+\sqrt{b}\) is \(\large a-\sqrt{b}\)

Answer 2

when you multiply them together, you get

\[\large (a+\sqrt{b})(a-\sqrt{b}) = a^2 - (\sqrt{b})^2\]

\[\large (a+\sqrt{b})(a-\sqrt{b}) = a^2 - b\]

Answer 3

So would the final answer be 6^2-(radical2)^2?

Answer 4

you can simplify further

Answer 5

6-(radical 2)?

Answer 6

6^2 = ??

Answer 7

36-(radical 2)^2?

Answer 8

is it 36-(radical 2)^2

Answer 9

The conjugate of \(\large 6+\sqrt{2}\) is \(\large 6-\sqrt{2}\)


When you multiply them together, you get


\[\large (6+\sqrt{2})(6-\sqrt{2}) = 6^2 - (\sqrt{2})^2\]


\[\large (6+\sqrt{2})(6-\sqrt{2}) = 36 - 2\]


\[\large (6+\sqrt{2})(6-\sqrt{2}) = 34\]


So,


Conjugate: \(\large 6-\sqrt{2}\)


Answer you get when you multiply original expression by conjugate: 34

Answer 10

Thanks a million
onbe more question though

Answer 11

(radical 2x-8)+10=6

Answer 12

i needs to solve and i only have 3 minutes

Answer 13

oh this is timed?

Answer 14

i have to go and i wanna finish this

Answer 15

well sorry I can't help with tests

Answer 16

its homework, im leaving for a roadtrip and dont want to have work when i get back on sunday

Answer 17

ok, but 3 min isn't a lot of time, sorry

esp for something this complicated

Answer 18

so maybe it's best to save it til you get back