Question

m = x1 + x2/2, v1 + v2/2

Answer 1

another in a series of fine fine worksheets i see

Answer 2

which of these problems are you doing? the last two are not exercises, they are formulas

Answer 3

the second to last one is the formula for the midpoint of a line segment
if the two points are \((x_1,y_1)\) and \((x_2,y_2)\) then the midpoint is
\[m=\left(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2}\right)\]

Answer 4

#5

Answer 5

the formula below it is the distance formula for the distance between two points

Answer 6

(I did the rest)

Answer 7

they are not questions to answer, they are just formulas

Answer 8

i don't know why there are there labelled #5 as if you were supposed to do something with them, they are formulas, not questions

Answer 9

then why is it on there? this teacher is weird about her worksheets

Answer 10

*they are there

Answer 11

what about the triangles??

Answer 12

YOUR TELLING ME?!!

Answer 13

weird doesn't really describe it
don't they believe in text books?

Answer 14

no of course not;) 21st century

Answer 15

they should really learn how to write math

Answer 16

arrogance is what it is

Answer 17

FF: She's actually a bio teacher

Answer 18

She's done this for the past 3 sections

Answer 19

yeah i remember you telling me this
i will give her the benefit of the doubt and believe that she knows and can teach bio
she should stick to that

Answer 20

in any case the two things under #5 are formulas, not questions to answer, so there is nothing to do there

Answer 21

she must be allergic to writing instructions on her work sheets

Answer 22

Hahahahahahaha

Answer 23

you're perfect. love you.

Answer 24

(blush) love you back

Answer 25

what if i screenshot this??? haha jk i would NEVEr. I respect teachers, but she doesnt know what the heck to do

Answer 26

i wouldn't if i were you but i am anonymous

Answer 27

i was def kidding

Answer 28

she will learn in time hopefully

Answer 29

WAIT what with the triangles she provided do you think she wants me to solve for x?

Answer 30

i guess so yes

Answer 31

help please

Answer 32

they are very famous triangles
do you know them ?

Answer 33

i'll take that as a "NO" ok we can do them

Answer 34

isoces

Answer 35

iscocles

Answer 36

both are solved via pythagoras
for a right triangle with legs \(a, b\) and hypotenuse \(h\) you have
\[a^2+b^2=h^2\]

Answer 37

no they are not "isosceles" they are "right" triangles
isosceles means two sides are the same length
these are right triangles, meaning one of the angles is a right angle

Answer 38

oops

Answer 39

you use \[a^2+b^2=h^2\] to find the side you don't know

Answer 40

for example in the first one you have
\[x^2+3^2=5^2\] or
\[x^2+9=25\]

Answer 41

okay:)

Answer 42

subtract 9 from both sides and get
\[x^2=16\] which means \(x=4\)
this is the famous "3 - 4 - 5 " right triangle

Answer 43

for the next one, \(x\) is the hypotenuse (longest side) so your only job is to solve
\[10^2+24^2=x^2\]

Answer 44

34?

Answer 45

or \[100+576=x^2\]
\[676=x^2\]
\[x=\sqrt{676}=26\]

Answer 46

really thats all???

Answer 47

not \(34\) but rather \(26\)
this is another famous right triangle "5 - 12 - 13"
if you double each side you get "10 - 24 - 26"

yes, that is all

Answer 48

you got all the other ones?