Factor the polynomial completely: 15y^2-60y^2
They are just like terms, so you can just subtract them as you subtract 60 from 15..
Simply tell : \[\large (15-60)y^2 = ??\]
@ineedyouubiebs ... do you have an idea of what the answer is? you got to try it :)
So far I have \[15y(1-4y)\]
If you want to learn it, then you have to try it.. :)
but @waterineyes just explained that they are like terms... so imply subtract them :P
when I subtact it I get -45
Precisely :D \[15y^2-60y^2\] \[-45 y^2\]
how does that lead to the rest of the problem though?
what do you mean? you are done :)
how can -45y^2 be the solution tough it seems weird and my teacher said to factor it
@waterineyes :D
Then is your question right?? Are you sure there are two \(y^2\) in your question?
that is the solution, right @waterineyes :)
Are you sure it is not \(15x^2 - 60y^2\) ?
If not, then like how @waterineyes said, you must have written the problem/question wrong...
@waterineyes where did you get the x from? you mean y?
@ineedyouubiebs please verify that you wrote the question/problem right...
My bad! I did say the problem wrong its suppose to be 15y-60^2 sorrry
Hey I am here only, why you guys are tagging me, Yellow colored post is coming again and again.. Hey, I have just suggested to look at your question again..
This is what I am saying..
lol sorry waterineyes....
Need not to be sorry, just kidding.. :)
\[15y - 60y^2\] Here you have to factor out \(15y\), can you do this?
yes, when I facot it I get 15y(1-4y)
i mean factor it
So you got what you want..
so it would be: \[15y - 60y^2\] \[15y( 1- 4y)\]
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