Question

Algebra 1 help square root.. :p

Answer 1

yah sure tll

Answer 2

What square roots do you need help with?? Jw.

Answer 3

6sqrt(v) - sqrt(4v^2) - sqrt(36v) + sqrt(v^2)

Answer 4

What grade are you in?

Answer 5

8th ... but im advanced so 9th grade math

Answer 6

- sqrt(4v^2) = - sqrt[ (2v)^2 ] = - |2v|


do you need help on the others too?

Answer 7

yes its an equation... adding and subtracting them..... how do i do that ^

Answer 8

let me try to show you the steps. Anything you dont understand just ask

Answer 9

ok thanks :)

Answer 10

6sqrt(v) - sqrt(4v^2) - sqrt(36v) + sqrt(v^2)
= 6sqrt(v) - sqrt[ (2v)^2 ] - sqrt[ v*6^2] + |v|
= 6*v^(1/2) - |2v| - 6*v^(1/2) + |v|


is this better for you?

Answer 11

well that's your teacher resolution?

Answer 12

I mean did you learn this from your teacher?

sqrt(v^2)=v;
sqrt(4v^2)=sqrt(4)*sqrt(v^2)=2v;


This 2 particular cases?

Answer 13

Yes.

Answer 14

i get -v :)

Answer 15

well i don't want to tell you that she is a bad teacher or something because i don't know her but when you have a square variable inside a square root you cant simply cut the 2 exponents.... You have to use the modulus sign as the variable could be negative aswell

Answer 16

is -v correct ?

Answer 17

Okay then. You answer the question and i'll delete my answer.

Answer 18

example:

sqrt(v^2)

if v = -2 then:
sqrt( (-2)^2) = sqrt(4) = 2

if v = 2 then:
sqrt( (2)^2) = sqrt(4) = 2


as you can see both -2 and 2 are a solution. Thats why when you cut the exponents you should use modulus signs

The correct answer would be

sqrt(v^2) = |v|

Answer 19

@Gabylovesyou you now should calculate that equations for the cases that |v| = -v and for |v| = v

Answer 20

v is not in my choices.....

Answer 21

3v
v sqrt(v)
-v
6v^2

Answer 22

-v is the correct answer. You are correct :)

Answer 23

ok thanks :)

Answer 24

yaaay. Gabylovesme

Answer 25

lol :p