Torque on a charge carrying loop in a magnetic field?
@.Sam.
@nincompoop
start with a drawing...
the current goes counter-clockwise as seen from above|dw:1368040364327:dw|imagine a uniform B-field...
Circular loop.. would it change anything?
no, the result you get can be most easily derived from a square loop, but holds for all shapes|dw:1368040519266:dw|
in our case it's a rectangular loop with sides a and b assume the current through the wire is I what is the force on each segment of wire due to the B-field?
alright so.. force on side a is.. in the -k direction.. right?
Idl(cross)B.. -j(cross)-i =-k ?
on b is zero.. and on the right vertical side is in the +k direction..
you can pick a coordinate system as you choose yes, force on the b sides is zero, and the force on the a segments is what in terms of a ?
let i be out of the board, j be right, and k be up
... at least that's my suggestion, I would avoid the unit vectors if we can
can we do it like i is right in the plane.. j is up in the plane.. and k is up outside the plane? i'm more comfortable with it..
umm. right hand/left hand rules confuse me.. so i prefer it like this.. And Torque=M(cross)B ?
yes your coordinate system is fne you will wind up with \[\vec\tau=\vec\mu\times\vec B\]but I thought we wanted to prove that...
umm no.. what would be the answer out of the 4 options?
and how? lol. i dont wanna get suspended for asking the answer. :P
what is the exact question? it asks you for the formula for torque on a circular current loop in a B-field is all?
This is the question..
oh, not a current-carrying loop, a charge carrying loop more interesting
um yeah.
well you should be able to figure out the minimum easily enough, so do that first
um. i am not sure about about it.
If it is actually a charge-carrying loop, then torque is zero, since magnetic fields do not act on fixed charges.
but if the loop is spinning with frequency f then the charges are moving...
Where is the full question, please?
This Vincent.
But i guess as its a circular loop so I is always perpendicular to B ( I will act tangentially) so.. 0 all.. am i right?
no.. ignore what i just said.
I don't think so|dw:1368041786740:dw|at this moment there will be torque
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