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Mathematics 9 Online
OpenStudy (anonymous):

Which graph shows the following inequalities? - 2 ≤ x + 5 < 7

OpenStudy (anonymous):

OpenStudy (compassionate):

Hello, I hope you're enjoying your stay at OpenStudy. Your fist step would be solving the inequality: - 2 ≤ x + 5 < 7 You can break it down into two inequalities -2 ≤ x + 5 and x + 5 < 7 The next step is solving each inequality. Can you do that?

OpenStudy (anonymous):

no, i dont understand how >__<

OpenStudy (compassionate):

Are you familiar with how to solve equations? If so, go ahead and solve this: x + 2 = 3 See if you can do it.

OpenStudy (anonymous):

well x = 1

OpenStudy (compassionate):

Okay, now can you solve x + 2 > 3

OpenStudy (anonymous):

x + 2 is greater than 3??

OpenStudy (compassionate):

Yes. CAn you solve it?

OpenStudy (anonymous):

No! i dont understand the question >__<

OpenStudy (compassionate):

It's the same as solving an equation. They are EXACTLY the same. x + 2 = 3 x - 2 + 2 = 3 - 2 x = 1 Now the inequality version x + 2 > 3 x - 2 + 2 > 3 - 2 x > 1

OpenStudy (anonymous):

so a > or < would always be the same as =?

OpenStudy (compassionate):

Yup! You work them exactly the same!

OpenStudy (anonymous):

nope okay i dont understand. - 2 ≤ x + 5 < 7 -2 = x + 5 = 7

OpenStudy (compassionate):

- 2 ≤ x + 5 < 7 You want to split it into two separate ones. -2 ≤ x + 5 x + 5 < 7 You basically want to take the middle terms (x + 5) and put them with the far left term and the far right term. Then solve them individually, and you'l lget the graph.

OpenStudy (anonymous):

i dont understand ;___;

OpenStudy (compassionate):

I'm going to use brackets ot make it easy to understand (1) < [x + 2] < (3) (1) < [x + 2] <-- you would solve this and you'll get a point on the graph [x + 2] < (3) <-- You would solve this, too, and get another point on the graph

OpenStudy (anonymous):

1 = 3 and 3 = 3??

OpenStudy (compassionate):

You're not getting this are you. -_-

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