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Chemistry 15 Online
OpenStudy (anonymous):

the volume of a certain gas is 29.3L at STP. what would be the volume of the same gas at 1.39 atm and 23 C?

sam (.sam.):

We'll find the number of moles of substance at STP, then use that to find the new volume using PV=nRT

sam (.sam.):

At STP, T=273.15K P=100000Pa R=8.31J K-1 mol-1 Can you find the moles?

OpenStudy (anonymous):

no :/ i suck at chemistry

sam (.sam.):

Whoops, we'll use P=1 atmosphere for simplicity, and R=0.082L atm K^-1 mol^-1 If you used PV=nRT, (1)(29.3)=n(0.082)(273.15) n=1.31moles

sam (.sam.):

Use back the formula PV=nRT but this time we use P=1.39 atm T=23 C (Remember to change to kelvin by adding 273.15 to 23C) n=1.31moles R=0.082L atm K^-1

OpenStudy (anonymous):

ty

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