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Chemistry 18 Online
OpenStudy (anonymous):

The specific heat of a substance is 2.01 J/g·°C. If given 10.3 grams of the substance and if 542 joules of heat is absorbed, what is the change in temperature of the substance? Answer 106 degrees C 10600 degrees C 26.2 degrees C 3.82 x 10−2 degrees C

OpenStudy (jfraser):

plug into the equation for heat change\[Q = m*C_P* \Delta T\]

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