Question

What is the solution of X^2+64=0?
-5
8
+-8
no solution

Answer 1

Simplifying
x2 + -64 = 0

Reorder the terms:
-64 + x2 = 0

Solving
-64 + x2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '64' to each side of the equation.
-64 + 64 + x2 = 0 + 64

Combine like terms: -64 + 64 = 0
0 + x2 = 0 + 64
x2 = 0 + 64

Combine like terms: 0 + 64 = 64
x2 = 64

Simplifying
x2 = 64

Take the square root of each side:
x = {-8, 8}

Answer 2

x=8

Answer 3

x=-8 too it's both

Answer 4

^ :D

Answer 5

lol

Answer 6

Thanks:)

Answer 7

Np.

Answer 8

np :D

Answer 9

haha

Answer 10

\[x^2+64=0 \] has only solutions in \[ \mathbb{C}\] though

Answer 11

no because you subtract 64 then it's x^2 = 64 and then you square root it all :) which is x=8 or x=-8 :D

Answer 12

ur finding x not b or c

Answer 13

yes, can you take the square root from a negative number?

Answer 14

Take a look at this:
http://www.wolframalpha.com/input/?i=x%5E2%2B64%3D0

Answer 15

i just know the answer i'm not really good at other things :/ sorry

Answer 16

Anyway, in Reals this one has no answer, so -> no solution

Answer 17

ummm idk O.o i think it's x= -8;8

Answer 18

Just check then, if x=8 is your solution, plug it into your equation and tell me if that gives you zero.

\[x^2+64=0\]
so you say x=8

\[(8)^2+64=64+64=128 \neq 0 \]

Answer 19

Now check for your other solution, you say x=-8 is a solution, so you plug that one in too:

\[(-8)^2+64=64+64=128\neq0\]