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Mathematics 13 Online
OpenStudy (anonymous):

Identify the asymptotes of the graph of each function. Then graph the function.

OpenStudy (anonymous):

\[y = \frac{ 1 }{ x + 2 }\]

OpenStudy (mertsj):

The vertical asymptote occurs where the denominator is 0. What value of x makes the denominator 0?

OpenStudy (anonymous):

-2.

OpenStudy (mertsj):

So the vertical asymptote is x = -2

OpenStudy (anonymous):

Okay, now to graph the function.

OpenStudy (mertsj):

|dw:1368222257318:dw|

OpenStudy (mertsj):

Now we know that the degree of the numerator is less than the degree of the denominator so that means that the y axis is a horizontal asymptote.

OpenStudy (mertsj):

So you need to figure out which two areas the two branches will be in.

OpenStudy (mertsj):

|dw:1368222410758:dw|

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