Question

With x-intercept =-3 and y =4 Find the equationof the line in slope intercept form

Answer 1

If the x-intercept is -3, what ordered pair is on the line?

Answer 2

3,0

Answer 3

(-3,0)

Answer 4

right

Answer 5

The first thing is, you'll have to get the slope:\[m = \frac{ y _{2} - y _{1} }{ x _{2} - x _{1} }\]where you have 2 points:

(-3, 0) and (0, 4)

which correspond to your intercepts.

Answer 6

And if the y intercept is 4, what ordered pair is on the line?

Answer 7

Next, you'll first have to use the point-slope equation of a line:\[y - y _{1} = m(x - x _{1})\]and you can use either of the two points for this.

Last, we can work on converting that equation to slope-intercept form:

y = mx + b

Answer 8

ok

Answer 9

So, your slope is:\[m = \frac{ 4 - 0 }{ 0 - (-3) } = 4/3\]

Answer 10

well tht was easy

Answer 11

That first equation point-slope, the last is slope-intercept. And that's it!

Answer 12

ok what about parallel to the line 4x +y=6, and through the point (-3,5)

Answer 13

Wait, hold on, I have to re-do something.

Answer 14

k

Answer 15

The point-slope form is:

y - 4 = (4/3)(x - 0)

So, the slope-intercept form is:

y - 4 = (4/3)x -> y = (4/3)x + 4

Answer 16

I had a typo before.

Answer 17

oh

Answer 18

ok, I see your next one, and I'll do it here, but the next ones should be in separate threads.

We have to get the slope and that is gotten by putting equation in slope-intercept form:

y = -4x + 6 where it is in the form: y = mx + b

So, slope is -4

That's step #1.

Answer 19

Now we use point-slope again:

y - 5 = (-4)[x - (-3)]

Now, we put that into slope-intercept:

y - 5 = -4x - 12

y = -4x - 7

And that's done. Ok, "new thread time" unless you have a question on this last one we just did.

Answer 20

ok new theard