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OpenStudy (anonymous):
OpenStudy (anonymous):
go into this site callec web 2.0 calc it type the problem into the calculator and BAM theres the answer! :) or better yet, get out paper and actually write out the problem
OpenStudy (anonymous):
and solve it that way
OpenStudy (loser66):
@onegirl do you have any idea?
OpenStudy (anonymous):
am i just going to substitute u or?
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OpenStudy (loser66):
yes, which one? u =?
OpenStudy (loser66):
try u = x^2 +1 then du =?
OpenStudy (anonymous):
is du the derivative of it? or
OpenStudy (loser66):
yes!! try, if you make some mistake, i correct it then, but the most important is trying!!
OpenStudy (anonymous):
ok
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OpenStudy (loser66):
don't worry, I dare not say anything further, but to this problem, I am ok
OpenStudy (anonymous):
okay i'll try it t
OpenStudy (anonymous):
okay for the derivative i got 2x
OpenStudy (loser66):
2xdx girl. ok, let put it in neat du = 2x dx , right?
OpenStudy (loser66):
got it?
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OpenStudy (anonymous):
okay
OpenStudy (loser66):
ok, now, we change the limit, have to. tell me, if x =0, u =?
OpenStudy (loser66):
do you know what I am doing?
OpenStudy (anonymous):
hmmm no
OpenStudy (loser66):
ok, let me explain. Originally, you have x, dx and limits respect to x
then, you change (substitute) to u, so, dx must change to du and limits must follow u, right?
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OpenStudy (anonymous):
yes
OpenStudy (anonymous):
so u will be 0 too right?
OpenStudy (anonymous):
Me? I live in USA
OpenStudy (loser66):
ok, take step!! forget my question, I thought you don't understand what I mean so, made that question to find out another way for you to come up the problem, now, you got it, no need more . take a look
OpenStudy (anonymous):
ok lol my bad
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