Question

Find the volume of solid that is obtained when region
Under the curve y=sqrt(x) over the interval {1,6}is revolved around the x-axis.

Answer 1

y=?????

Answer 2

Just updated, sorry.

Answer 3

Using the disk method http://library.thinkquest.org/3616/Calc/S3/TDM.html

\[\huge V = \pi \int\limits_{1}^{6} (\sqrt x )^2 dx\]

Answer 4

not very helpful mate,

Answer 5

Umm..okay... if you read the link it might have been. The radius of the disk would be sqrtx, thickness is dx, the area of the integral is under the curve sqrtx from x=1 to x=6.