Question

Which is the solution to |2x - 4| > 8

Answer 1

I'd square both sides to solve
(2x-4)^2>8^2

Answer 2

Do you know how to continue from here?

Answer 3

I did it but I end up getting the square root of x = 24 and then when I factor it , the answer is not one of the choices

Answer 4

Hello,

You are solving absolute values. The first step is to eliminate the 4. Do you know how?

Answer 5

don't you just add 4 to the other side

Answer 6

Correct. Absolute values means that you are 4 spaces from zero.

So, add the 4 to the eight.

Answer 7

which gives me 2x>12

Answer 8

Now divide the 2.

Answer 9

X > 6 , but that is not one of my choices that's why I have been confused

Answer 10

Okay, I understand what you're asking. One second please.

Answer 11

x = 2 or x = 6
-2 < x < 6
x < -2 or x > 6
x < -6 or x > 2

Answer 12

\[x > 6 ----- x < -2\]

Answer 13

The anwer would be C.

I'll allow Mathslover to explain how we came to the answer. I see him typing.

Answer 14

well please wait then for 2 minutes.

Answer 15

If you don't feel like explain, then I can.

Answer 16

see we have :

\(\large |2x-4| > 8\)

Now I can write this as : \(\large 2|x-2| > 2 * 4\) \(\implies |x-2| > 4\)

So we have two cases here : either x-2 > 4 or x-2 < -4

so : \(\large x > 6\) as x-2 > 4

and x < -2 as x-2 < -4

so I have : \(\large x \in (-\infty , -2 ) \space \cap (6 , \infty ) \)

Answer 17

ohhh because its absolute value you have to do the both positive and negative forms...
thanks everybody for helping I really appreciate it

Answer 18

This is the shortest and logical method for solving this question.

Answer 19

Yes - Brand, because the absolute value of any number means the numbers that are x spaces from zero.

So if I had I 4 I, I positive and negative 4 are four spaces from zero.

Answer 20

The method suggested by @.Sam. was also good but that would have been longer than the above mentioned method. And thanks @Compassionate for giving me the chance to put here my opinion .

Answer 21

No problem. I hate to snipe other users.

Answer 22

:)

Answer 23

For some addition methods, the way I solved it was:

|2x-4| > 8

Either:

2x - 4 > 8
2x > 12
x > 6

Or:

-|2x - 4| > 8
-2x + 4 > 8
-2x > 4

Answer 24

x > -2

Answer 25

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Best of luck!