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What is the general form of the equation of a circle with a center at the (–4, 2) and a radius of 9? I got (x + 4)^2 + (y – 2)^2 = 81 I just wanted to confirm whether it was correct or not. I'm pretty sure the signs change making it (-4,2) and the 81 is the diameter or circumference.
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@amistre64
81 =r^2
(x-x1)^2+(y-y1)^2=r^2
@dricboylan
the general setup of a circle centered at (a,b) with radius r is: (x-a)^2 + (y-b)^2 = r^2 (x+4)^2+ (y-2)^2 = 9^2 -a = 4 -b = -2 (a,b) = (-4,2) r^2 = 9^2 = 81
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so thats fine
the "signs change" is a good thing to remember :)
So I was right?
you were right
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