Solve for y, then differentiate to get y' in terms of 'x' ; xy+2x+3x²= 4

Question

anonymous · Answer

$$xy+2x+3x^2=4$$
$$x(y+2+3x)=4$$
$$y+2+3x=\frac{ 4 }{ x }$$
$$y=\frac{ 4 }{ x }-3x-2$$

anonymous · Answer

That was solving for y.
1st step was to factor an x on the left hand side.  
Then the second step was divide both sides by x
Then finally minus 2 & 3x from both sides.

anonymous · Answer

any questions? Before I move on to y'

anonymous · Answer

Hint: to take the derivative of the right hand side (with respect to y) you may use the power rule (I think that's what it's called).

anonymous · Answer

Ohhh okay no no questions.

anonymous · Answer

Thanks btw !

anonymous · Answer

notice that $$\frac{ 4 }{ x }=4*x ^{-1}$$

anonymous · Answer

y'=-4x^(-1-1)-3=-4x^-2-3=-4/x^2  -3

anonymous · Answer

got lazy sorry this is how it is really written
$$y'=-4x ^{-1-1}-3=-4x ^{-2}-3=\frac{ -4 }{ x ^{2} }-3$$

anonymous · Answer

Ohh okay !! thanks

anonymous · Answer

So basically im finding y'

anonymous · Answer

@mashe  im stuck please help

anonymous · Answer

Sorry burhan101 I logged off shortly after posting...I didn't neglect you on purpose...do you still need help?