Question

How do I convert the polar equation r=1-cos theta into a rectangular equation?

Answer 1

This question is on an exam review written this way? So I think it is correct.

Answer 2

I can do coordinate conversions too. Thanks for trying.

Answer 3

Anyone else?

Answer 4

lemme check a bit

Answer 5

Thanks

Answer 6

Still thinking?

Answer 7

I am still stuck

Answer 8

hehe

Answer 9

gotten anywhere?

Answer 10

No. I am working on a different one because I don't know what to do. Still hoping for help!

Answer 11

Any ideas?

Answer 12

I'll show thus far what I'm checking :)

Answer 13

$$
r=1-cos(\theta) (\times r)\\
r^2=r-rcos(\theta)\\
\text{bear in mind } rcos(\theta)=x\\
r^2=r-x\\
\text{now if you keep in mind that } \boxed{r^2=x^2+y^2} \ \&\& \ \boxed{r=\sqrt{x^2+y^2}}\\
$$

Answer 14

from there, I gather you'd just need to solve for "y" or f(x)

Answer 15

looks a bit convoluted, but is thus far what works :|

Answer 16

That method will give you a fair bit of algebra.

Answer 17

Is there a better method?