Question

This circle, with center point Q, has a radius of 10 centimeters. The length of the minor arc NP is 20.42 centimeters. To the nearest degree, what is the value of x? Picture will be posted.

Answer 1

@kausarsalley

Answer 2

@RadEn

Answer 3

\[A_L=\frac{ x^0 }{ 360^0 } \times 2\pi r\]
A(L)=Arc length (which was given to be 20.42
x=the central angle of the arc which is what you are finding
r=radius of the circle

Answer 4

plug in the values you have and find x...

Answer 5

are you sure the second part of the formula is not πr^2? its 2πr ?

Answer 6

yes....it is 2pi r (because we are finding the arc length this time around..
you would use pir^2 if it had to do with the area of the sector....

Answer 7

ok

Answer 8

ok, continue

Answer 9

\[20.42=\frac{ x^0 }{ 360^0 } \times 2\pi \times 10\]

Answer 10

so can you find x from there??

Answer 11

yes

Answer 12

actually no can u help me more

Answer 13

so 20.42= x/360 × 62.8

Answer 14

now x times 20.42?

Answer 15

you are right for the 1st step..

Answer 16

so since what i just said isn't right, do you do 62.8 times 360?

Answer 17

its supposed to be 20.42 divided by 62.8

Answer 18

oh ok

Answer 19

wait why

Answer 20

so after, what do you do??

Answer 21

\[20.42=\frac{ x }{ 360 } \times 62.8\]

Answer 22

then it will be 0.325 = x/360

Answer 23

then cross multiply
x= 117.05... so 117

Answer 24

yes...that is right...but a very slight mistake...its supposed to be 117.06 therefore 117 which you got right!

Answer 25

my calculator said 117.057

Answer 26

which rounds to 117 .. whatever i got it thnx

Answer 27

yw......(: