Question

algebra 1

Answer 1

a) just add the xs and the numbers together like you normally would
b) just subtract the sum of the smaller triangle's perimeter from the bigger one
c) just plug in x=3 for the equations in part a

Answer 2

the frist one for the first triangle is wrong, it would be 4 x 3 + 2 =14

Answer 3

it's right otherwise
to find the perimieter, you just add up all of the x's and the numbers, so the larger triangle would be: (4x+2)+(5x-4)+(7x+7)

Answer 4

yep

Answer 5

Sorry, had to step away for a bit... just add the legs of the triangle
the x is a variable

Answer 6

part a looks good

Answer 7

both

Answer 8

yes

Answer 9

no, the large triangle has perimeter 16x+5, now we are subtracting 4x+5 from that

Answer 10

yes

Answer 11

err, other way around, you are subtracting the small from the big one so it's 16x-4x = 12x

Answer 12

yes

Answer 13

Thanks! But now what do I do for "c"

Answer 14

your first reply had the answer for c which is right

Answer 15

now just add those values up for both triangles

Answer 16

just add up 14+11+28 and 6+10+1

Answer 17

yes

Answer 18

14+11+28 gets you the larger triangle
6+10+1 gets the smaller triangle

Answer 19

perimeter = sum of the legs of the triangles
the legs for the larger triangle as you found are 14, 11, 28
the legs for the smaller triangle are 6, 10, and 1

(which now that i think about it, are geometrically impossible)

Answer 20

i have to step away again, good luck...

Answer 21

a. 16x+5;4x+5
b. 16x+5-(4x+5)=12x
c. 16(3)+5=53; 4(3)+5=17