Question

log(4x+1)=1+log(x-1)

Answer 1

Combine like terms with each others :
Log(4x+1)-Log(x-1)=1
Then Use Log property
Can you continue ?

Answer 2

the left hand side becomes
\[\log\left(\frac{4x+1}{x-1}\right)=1\]

Answer 3

Then change it to exponential

Answer 4

if you cant put a negative in the log what happens to the left hand side? or does x-1 become x+1

Answer 5

After you change it to exponential ,it will be
10^1=(4x+1)/(x-1)
multiply by (x-1) to both sides
and solve for x

Answer 6

There is a variable in log (x-1) in order to avoid being a negative though

Answer 7

10x-10 = 4x+1
10x = 4x + 11
6x = 11
x = 11/6
i feel like thats not right lol

Answer 8

\[\Huge \color{Red}{That's~Right~♥ ❤ ❥}\]

Answer 9

OMG :D yay :) so is it most proper to write as a fraction or as a decimal

Answer 10

it says "type an exact answer using radicals or log functions as needed"

Answer 11

I think fraction would be better :P