Question

6^x-40 * 6^-x=6

Answer 1

\[6^{x-40}*6^{-5}=6\]

Answer 2

is that it?

Answer 3

So sorry, no, I will clarify \[6^{x}-40 * 6^{-x}=6\]

Answer 4

you factor out 6^x

Answer 5

Let y = 6^x

Answer 6

\[y-\frac{40}{y}=6\]

Answer 7

\[\frac{y^2-40}{y}=6\]

Answer 8

\[y^2-40=6y\]

Answer 9

\[y^2-6y-40=0\]

Answer 10

Factor, solve, resubstitute.

Answer 11

(y-10)(y+4)= 0?

Answer 12

yes

Answer 13

ok so now that it is factored, how would I solve it?

Answer 14

y= 10 and y =-4
two solutions

Answer 15

thats what I would plug in for my exponents? my problem is asking "x = ?"

Answer 16

so y= 6^x

Answer 17

6^x = 10 and 6^x= -4, since 6^x cannot = -4 then solve for 6^x=10

Answer 18

should be around 1.3

Answer 19

to solve for x you take the log of both sides ... log 6^x = log 10 then put the x in front of the log 6 according to log rules. you get x log 6 = log 10. divide both sides by log 6 and you get log10/log 6 = 1.285 = x

Answer 20

byeee

Answer 21

Ok, I think I get it, thank you