Question

solve for the polynomial inequality
x^3 + x^2 +64x +64>0

Answer 1

factor it out

Answer 2

First, change it into an equation and get the zeros.

Answer 3

x^2(x+1)+64(x+1)

Answer 4

(x^2+64)(x+1)>0

Answer 5

what values of x = 0? and so the answer = the numbers bigger than those values

Answer 6

x = -1
x^2 = -64

Answer 7

well you cant do anything about x^2=-64 so it's just x = -1

Answer 8

so x>-1 is the answer

Answer 9

is that considered a solution set, though?

Answer 10

when oyu're solving for the polynomial inequality you're solving for x

Answer 11

so yes x>-1 is considered a solution

Answer 12

it means all numbers larger than -1, alternatively you can make it (-1,infinity)

Answer 13

ok, it asks for interval notation so I will use (-1, infinity)