Question

2sin(x)-sqrt(2)=0

Answer 1

add sqrt(2) to both sides

Answer 2

intervals for x ?

Answer 3

у меня получилось пи/4 + 2пи n, n принадлежит z

Answer 4

I guess it's n*pi/4+2*n*pi?

Answer 5

точно нет

Answer 6

wow I wish I spoke Russian

Answer 7

Me too xD

Answer 8

this is what google translate says for the 2 before

I got pi / 4 + 2PI n, n z belongs

Answer 9

The equation is sin(x)=sqrt(2)/2 which is correct when x=45º=pi/4 if the interval is 0<=x<=2pi x=pi/4 and x=pi/4+pi/2

Answer 10

@knock Уравнение есть грех (х) = SQRT (2) / 2, которое считается правильным, если X = 45 º = пи / 4 Если интервал 0 <= X <= 2 пи х = пи / 4 и х = пи / 4 + пи / 2

Answer 11

2sin(x)-\[2\sin(x)-\sqrt{2}=0\]
\[2\sin(x)=\sqrt{2}\]
\[\sin(x)=\frac{ \sqrt{2} }{ 2 }\]
\[\sin(x)=\frac{ 1 }{ \sqrt{2} }\]
\[x=\sin^{-1} \frac{ 1 }{ \sqrt{2} }\]
\[x=\frac{ \pi }{ 4 }\]
or
\[x=\frac{ 3\pi }{ 4 }\]

Answer 12

Для этого, sin(x)=\(\frac{\sqrt{2}}{2}\), затем использовать

Answer 13

if no interval is given ,then we can get infinite solutions by adding 2npi to x=pi/4,3pi/4 where n is an integer.