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d/dx(integral cos(t^2)dt)
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\[\frac{ d }{ dx }\int\limits_{}^{}\cos(t ^{2})dt\] right?
If that is the thing you differentiate due to a constant and then the whole thing become 0.
I don't think so, it is= cos (t^2)
yes it is ddx∫cos(t2)dt
how do you find the definite integral
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by definition, derivative cancel out with integral and you get the original function without calculating any thing
oh alright. Thank you.
need more explanation? need more example?
so basically you are saying that d/dx and integral cancel which leaves you with the original equation of cos (t^2) dt right?
no dt. just cos (t^2)
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for example: if |dw:1368447884193:dw|
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