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Mathematics 19 Online
OpenStudy (unklerhaukus):

\[10, 15, 22, 33, 47, ?,\]

OpenStudy (amistre64):

5 7 11 14 2 4 3 2 -1 3 that aint it

OpenStudy (unklerhaukus):

hmm,

OpenStudy (loser66):

@amistre64 , logic, please

OpenStudy (amistre64):

i was trying a difference level to see if at some point there was a constant row .... but theres not enough numbers to be sure

OpenStudy (loser66):

got what you mean

OpenStudy (amistre64):

.......................... 60 ; would be fine, but does not necessarily mean 5 7 11 14 13 its correct :) 2 4 3 -1 2 -1 -4 -3 -3

OpenStudy (unklerhaukus):

60 is not the answer i am looking for,

OpenStudy (amistre64):

we can create a polynomial that hits all those values .... but then thats not neccesarily a "correct" method either .... some context would be helpful

OpenStudy (unklerhaukus):

maybe a picture

mathslover (mathslover):

is it 67?

OpenStudy (unklerhaukus):

close

mathslover (mathslover):

oh.

mathslover (mathslover):

68 ....

OpenStudy (unklerhaukus):

but why?

mathslover (mathslover):

Is it correct? I ensure, I am not making any guess :)

OpenStudy (amistre64):

y = -x^4/8+13x^3/12-11x^2/8+65x/12+10 ironically enough, that get (5,60) too :)

OpenStudy (unklerhaukus):

so what comes next ?

OpenStudy (unklerhaukus):

ok, next one: 10 12 15 18 22 27 33 39 47 56 68 ?

mathslover (mathslover):

82

mathslover (mathslover):

oops or is it 91?

OpenStudy (unklerhaukus):

what is the pattern?

mathslover (mathslover):

They follow the same pattern of every multiple of ten. E-6 : [there will be 6 values for each multiple of 10, for E-6 : 20% tolerance ] 10, 15, 22, 33, 47, 68, then it continues 100, 150, 220, 330, 470, 680, 1000 etc. right?

mathslover (mathslover):

The E-12 series will have 10% tolerance 10,12,15,18,22,27,33,39,47,56,68, 82(I think its 82) then it continues

mathslover (mathslover):

its practical electronics ..

OpenStudy (unklerhaukus):

But what is this pattern they are following, ? How does the % number determine the next term in the sequence?

mathslover (mathslover):

Well with the help of the % , the error is calculated, right?

OpenStudy (unklerhaukus):

i guess so, i would like to know the details though

mathslover (mathslover):

Please refer to the pm. And I will come back after a short sleep and will try to explain it clearly. I have also forgotten something about this topic, I studied it 1.5 years ago, may be I need some source to refresh my knowledge. I will prefer books though.

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