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Mathematics 20 Online
OpenStudy (anonymous):

Can someone please help me. I need a little help. I don't want answers.

OpenStudy (dobby1):

whatcha need

OpenStudy (anonymous):

what does (A ∩ B) ∪ (~A ∩ C) mean?

OpenStudy (dobby1):

no idea

OpenStudy (anonymous):

not extremely helpful. @Dobby1

OpenStudy (anonymous):

Know anyone who is good at math?

OpenStudy (dobby1):

so sorry um i dont know let me find someone

OpenStudy (anonymous):

I can tag people. thanks anyways.

OpenStudy (dobby1):

@amistre64

OpenStudy (dobby1):

@terenzreignz

OpenStudy (anonymous):

Given the function g(x) = 8x − 2, compare and contrast g(−2) and g(4). Choose the statement that is true concerning these two values. The value of g(−2) is larger than the value of g(4). The value of g(−2) is the same as the value of g(4). The value of g(−2) is smaller than the value of g(4). The values of g(−2) and g(4) cannot be compared. can you help with this one. I am no good at this type of thing.

terenzreignz (terenzreignz):

This is... an entirely different question now...

OpenStudy (anonymous):

I know. i am doing a math test and these are the two i am stuck on. i do not want answer oly for you to help explain them both.

OpenStudy (anonymous):

@terenzreignz are you gonna help?

terenzreignz (terenzreignz):

OS is incredibly slow for me... I was asking if perhaps you can post the choices for this: (A ∩ B) ∪ (~A ∩ C) ?

OpenStudy (anonymous):

Here's a good link to explain the "U" symbols. http://en.wikipedia.org/wiki/List_of_mathematical_symbols

OpenStudy (anonymous):

∪ means "OR", ∩ means "AND", I believe

OpenStudy (anonymous):

I think "~" means "NOT", but that's a guess for me

OpenStudy (anonymous):

I solved that one. I had to watch a bunch of tutorials online for it. Sorry. can you help with the other one. @MichelCarroll

terenzreignz (terenzreignz):

g(x) = 8x - 2 To find g(-2) and g(4), simply replace the x in "8x - 2" with -2 and 4, respectively.

OpenStudy (anonymous):

how would i solve that. I really do not know how to do it. Please just give me the steps.

terenzreignz (terenzreignz):

Okay, a few examples, perhaps? We have g(x) = 8x - 2 Let's say we have to find g(3) Then we replace the x in the function with 3... like so: g(3) = 8(3) - 2 Simplify... g(3) = 24 - 2 g(3) = 22. Another: say we need g(-1) As in the first example, replace x with -1... like so: g(-1) = 8(-1) - 2 Simplify again... g(-1) = -8 - 2 g(-1) = -10 Having said that, can you now find g(-2) and g(4)

OpenStudy (anonymous):

for g(-2) it is 9 correct? i am starting on the other.

OpenStudy (anonymous):

g(4) is going to end up g = 7.5?

terenzreignz (terenzreignz):

No, it's not. Try again, replace x with -2...

OpenStudy (anonymous):

8x-2 is -16

terenzreignz (terenzreignz):

that is true... so how did you end up with 9?

OpenStudy (anonymous):

subtract 2 and you get -18. i divide by -2 and got positive nine.

terenzreignz (terenzreignz):

Why did you divide by -2?

terenzreignz (terenzreignz):

As I recall, g(x) = 8x - 2 there is no division by -2 involved... is there?

OpenStudy (anonymous):

would i multiply. i thought you divided to get g.

terenzreignz (terenzreignz):

ahh, I see LOL

terenzreignz (terenzreignz):

Here's the problem... \[\Large g(x) \color{red}\ne g\cdot x\] g(x) is not g multiplied by x :) It's confusing at first, but you'll get it in time...

OpenStudy (anonymous):

what do you mean. what is g x? would my final answer be g(-2)=-18 and the other one be g(4)=30

terenzreignz (terenzreignz):

Yes. Exactly :D

terenzreignz (terenzreignz):

So, now that you know what g(-2) and g(4) are, I guess the answer to your question should be easier to get? :)

OpenStudy (amistre64):

"you are doing a math test" is not a good thing to post on here .....

OpenStudy (anonymous):

so my final answer to the problem is going to end up being c

OpenStudy (anonymous):

I am asking for help. i only wanted to learn how to do it so i can finish the test. I see nothing wrong with having help figuring it out. nobody has told me answers and i do not want them.

OpenStudy (amistre64):

i understand that, but there are affiliations that check this site to determine if their students are using it contrary to their own codes of conduct. its would simply be best if you did not provide that information is all .....

OpenStudy (anonymous):

thank you @terenzreignz for helping me. that is all i did not understand. Thanks @amistre64 for telling me that. i honestly just thought you were annoyed i was asking for help on an exam. lol

OpenStudy (amistre64):

'sok :) i just dont want to have to enforce our own policy on someone who is not really trying to cheat is all

OpenStudy (amistre64):

good luck

terenzreignz (terenzreignz):

Good luck :) The name's TJ :D

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