identify the asymptote: (1/x^2) + 3
The Possible answers are: x=2,y=-3 x=2,y=3 x=-2,y=-3 x=-2,y=3
i disagree with all the possible answers
well those are the ones there are
well they're wrong
x=2 and x=-2 are not asymptotes simply because if you substituted them in, you would get an answer
ignoring the 3 for now cause all that will do is shift hte graph up 3 units and looking at 1/x^2 recall that the denominator cannot be equal to 0 that means x cannot be _____ and that value will be the x- asymptote
so its either c or d
no, as i said, none of the answer choices are correct
well oneof them must be close to the correct answer
none of them are correct or you did not provide the full question
only 2 are partly correct and neither of them are any close to the answer
here is the full question Identify the asymptotes of the graph: y=(1/x+2) + 3
thts what it says
that is a significantly different question than what is posted above
oh ya duh my mistake srry
for the parent graph 1/x the x and y asymptote would both be zero 1/x +b y asymptote would be zero and y asymptote would be "b" because the values/graph will not be able to cross y=b to determine x asymptote the denominator cannot be equal to zero so you set the denominator equal to zero and solve for x and x will be the x asymptote
So its B then
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