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Mathematics 19 Online
OpenStudy (anonymous):

Give two values of between 0° and 180° for the given value of sin . Express your answers to the nearest degree. 0.9900

OpenStudy (jdoe0001):

stick it in your calculator :), get the arcsin()

OpenStudy (jdoe0001):

or \(sin^{-1}\)

OpenStudy (anonymous):

i don't understand how to calculate it the right way though, i keep getting the wrong answer

OpenStudy (jdoe0001):

make sure your calculator is in Degree mode :|

OpenStudy (jdoe0001):

as opposed to Radian

OpenStudy (anonymous):

1.4292568535 is the answer i keep getting .-.

OpenStudy (jdoe0001):

right, that's the proper value for Radians

OpenStudy (jdoe0001):

so you have your calculator in Radian mode, but the answer is required in Degrees

OpenStudy (anonymous):

ooh, so if i just used a trig chart for radians to degrees i should get the answer right?

OpenStudy (jdoe0001):

ahemm, calculators do both :|, if in Radian Mode, the trig functions give the Radian value, if in Degrees, they give the Degree value, yours is in Radian, but you need Degrees

OpenStudy (jdoe0001):

so just change the Mode in the calculator to Degree

OpenStudy (jdoe0001):

and redo the \(sin^{-1}\)

OpenStudy (anonymous):

got it! it's 81.9, but that doesn't completely answer my question, it's asking for something in between two numbers

OpenStudy (jdoe0001):

it's asking for something between, well, THERE :) so 81.9 degrees is in the I Quadrant Sine function is positive on the Quadrants Y is positive, so the other will be there

OpenStudy (anonymous):

okay thanks :D

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