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How do you eliminate the parameter for this? x = sqrt t , y = 3t + 7
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ok
Square both sides of this equation: x = √t then substitute t to what it equal to.
And, ladies and gentlemen, this is how you eliminate this parameter.
@geerky42 so would it be y = 3 √x + 7, x ≥ 0
or does the squareroot cancel out completely?
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t = √x ? I don't think so.
x = √t x² = ( √t )² x² = t
Is this clear? @serinaaa
@geerky42 y = 3x^2 + 7 ?
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@geerky42 Thank you!!!!
No problem.
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