Help with polynomial functions please? :)
1.Graph the function f(x) = (x + 3)3 by hand and describe the end behavior.
y = (x + 3)^3 x = -3 => critical point, and the point of inflection. x < -3 it concave down , x > -3 concave up
Do you mean\[f(x)=(x+3)^3\]?
@AnimalAin yes sorry :)
y = (x + 3)^3 x = -3 => critical point, and the point of inflection. x < -3 it concave down , x > -3 concave up
y = (x + 3)^3 x = -3 => critical point, and the point of inflection. x < -3 it concave down , x > -3 concave up
y = (x + 3)3 = 3x + 9 i assume you mean times three this is of the form y = mx + b the slope is 3 and the y intercept is 9, a line or you may mean y = (x + 3)^3 this looks just like y = x^3 only shifted to the left 3. the functions is zero at -3 to the right it goes to + infinity and to the left is goes to - infinity
End behavior is what the function does as x gets a long way from the origin. In this case, the end behavior tends to positive infinity as x gets large in a positive direction, and toward negative infinity as x gets really negative.
multiply 3 into the equiation in the bracket : F(x)= 3x + 9 so if x = 0 => F(x)=9 x=1=> F(x)=9 x=2=> F(x)=12 x=3=> F(x)=15 x=4=> F(x)=18 It is a linear finction, and it increases by 3 (3x).
As noted, there is an inflection point at (-3, 0). The graph looks like y=x^3 moved three units to the left.
@smartguy1124 You don't Get a medal you just copped and pastes that..
i know sorry
pasted.*
sorry
haha thankyou for the effort guys! I appreciate it, even if you copy and pasted :p @smartguy1124 @AnimalAin
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