Question

How do you solve: \[-\frac{1}{3}y-2=-6\]

Answer 1

Add 2 to both sides. then multiply by -3 both sides.

Answer 2

Does that help? @andriod09

Answer 3

Sorry, had to get water. Kind of. I'm stuck at this: \[-\frac{4}{1}(-\frac{3}{1})\]

Answer 4

-4*-3=?
(-)*(-)=(+)

Answer 5

Oh, so you do multiply the tops and leave the bottoms alone?

Answer 6

\[\frac{4}{1}=4\]

Answer 7

Don't I feel stupid. >.<

Answer 8

if a number is divided 1 then u get the same number as the answer

Answer 9

still stuck? Am sorry if i have confused u more.

Answer 10

@andriod09

Answer 11

Sorry, browser crashed.

Answer 12

\[-\frac{1}{3}y-2=-6\]
Add 2 both sides. then u will get
\[-\frac{1}{3}y-2+2=-6+2\]
\[-\frac{1}{3}y+0=-4\]
\[-\frac{1}{3}y=-4\]
Multiply by -3 both sides.
\[-3*-\frac{1}{3}y=-4*-3\]
\[-\cancel3*-\frac{1}{\cancel3}y=-4*-3\]
\[-1*-\frac{1}{1}y=-4*-3\]
\[-1*-1y=-4*-3\]
\[1y=-4*-3\]
\[y=-4*-3\]
Does that help? @andriod09

Answer 13

I already got it. Thanks.

Answer 14

Welcome:)